MTH3008 Weekly Problems 9
Original Documents: mth3008 weekly problem sheet 9.pdf / mth3008 weekly problem sheet 9 handwritten solutions.pdf / mth3008 weekly problem sheet 9 solutions.pdf
Vibes: More Christoffel-symbol marathon, now with a final payoff - the Riemann-Christoffel Tensor for two surfaces. Every problem reduces to “find the diagonal metric, read off , drop into 8.1’s four cases.” The curvature calculations in 9.4 and 9.6 follow the unit-sphere template from lecture 18.
Used Techniques:
- Christoffel Symbols formula restricted to orthogonal coordinates (8.1 cases).
- Raising with (diagonal).
- Riemann-Christoffel Tensor formula .
- In 2D, only is independent (all others either vanish or are related by antisymmetry).
9.1. Christoffel Symbols for Exponential Coordinate Scaling
Question
For with coords, find all and .
Basis. , , . Orthogonal.
Metric. , , . Inverse: , , .
Nonzero metric derivatives. , ; every other derivative is zero.
First-kind (8.1 case ):
(No or survive because every cross-derivative vanishes.)
Second-kind:
All others zero.
9.2. Christoffel Symbols for a Mixed Exponential-Trigonometric-Logarithmic Map
Question
For , find all Christoffel symbols.
Basis. , , . Orthogonal.
Metric. , , . Inverse: , , .
Nonzero metric derivatives. ; ; .
First-kind - only diagonal cases survive:
Second-kind:
All others zero.
9.3. Orthogonal Coordinates with Given Scale Factors
Question
Orthogonal system with , , . Find all Christoffel symbols.
Metric. :
, , .
Nonzero derivatives.
- ,
First-kind (8.1 cases), nonzero only:
Second-kind via (no sum, diagonal metric):
All others zero.
9.4. Christoffel Symbols and Curvature of the Unit Sphere
Question
Sphere parametrised by , , . (1) Compute . (2) Show the surface has non-zero curvature.
1) Christoffel symbols. As a 2D surface (only matter).
, .
Metric: , , . Inverse: , .
Nonzero derivative: .
First-kind: , .
Second-kind:
All others zero.
2) Riemann-Christoffel tensor. Compute the key component :
- .
- (since ).
- : both and terms vanish ( and ).
- : contributes .
Therefore:
Since on the open interval , the sphere has non-zero curvature - it is not Euclidean. ✓
9.5. Surface of Revolution with Unit-Speed Meridians
Question
parametrised by , with . Find all Christoffel symbols.
Basis.
Metric. Using :
Orthogonal; , .
Nonzero derivative. .
First-kind: , .
Second-kind:
All others zero.
9.6. Curvature of the Surface of Revolution
Question
Using the Riemann-Christoffel tensor, determine whether the surface of problem 9.5 has zero curvature (assuming ).
Apply the formula with :
- .
- .
- : all contributions vanish ().
- : only contributes, .
Therefore:
Conclusion. Since , the surface is Euclidean (flat) iff , i.e. iff is linear in . Generically , so the surface has non-zero curvature.
When is a surface of revolution flat?
means . Combined with , this constraints , a constant. Two special cases:
- : constant ⇒ cylinder (radius ).
- : cone (straight slanted meridian).
Both are developable (flat) surfaces - consistent with zero curvature. Everything else (sphere, torus, paraboloid, …) has curvature.